Friend Links: SKF Bearing FAG Bearing NSK Bearing Timken Bearing KOYO Bearing

High Carbon Chromium Steel Needle Roller Bearings NUTR45

150 sold in last 19 hours
Hurry! Over 125 people have this in their carts

Specifications

Bore Diameter 45 mm
Outer Diameter 90 mm
Thickness 100 mm
Material High Carbon Chromium Steel
Type Needle Roller Cam Follower

Description

Precision-engineered needle roller cam follower made from high carbon chromium bearing steel for superior durability and load capacity. Ideal for industrial applications requiring high precision and reliability.

  •  Size Guide

    Size Guide

  •  Delivery & Return

    Delivery

    Store delivery FREE

    1-3 working days

    Home or collection point from £35.00 FREE

    On all your orders for home or collection point delivery

    Returns

    Return

    We will accept exchanges and returns of unworn and unwashed garments within 30 days of the date of purchase (14 days during the sales period).

    Returns in store FREE

    Your return will usually be processed within a week to a week and a half. We’ll send you a Return Notification email to notify you once the return has been completed. Please allow 1-3 business days for refunds to be received to the original form of payment once the return has been processed.

  •  Ask a Question
  Estimated Delivery: Mon, Apr 06 – Fri, Apr 10
  ... people are viewing this right now

  Share
Guaranteed Safe Checkout

Basic Info.

Material
Bearing Steel

Precision Rating
P0 P6 P5 P4

Vibration Level
Z1 Z2 Z3 Z4

Feature
Long Life, High Speed, Low Noise

Service
OEM ODM

Transport Package
Carton Pallet

Trademark
BDL

Origin
China

HS Code
8482102000

Production Capacity
1000000

SKU: 70368828eb20 Category: 
My Cart
Wishlist
Recently Viewed
Categories
High Carbon Chromium Steel Needle Roller Bearings NUTR45

High Carbon Chromium Steel Needle Roller Bearings NUTR45

Request a Call Back

    High Carbon Chromium Steel Needle Roller Bearings NUTR45

    High Carbon Chromium Steel Needle Roller Bearings NUTR45

    Ask a Question